In a population at Hardy-Weinberg equilibrium, the frequency of a recessive disease is 1 in 10,000 individuals. What is the approximate carrier frequency?
Show answer and explanation
Correct answer: 1/50
If q-squared = 1/10,000, then q = 1/100 and p is approximately 1. The carrier (heterozygote) frequency is 2pq = 2(1)(1/100), which is approximately 1/50.
Keep practicing
More Population genetics questions
- Which of the following conditions must be met for a population to maintain Hardy-Weinberg equilibrium?
- A rare autosomal recessive disorder affects 1 in 40,000 individuals. What is the approximate allele frequency of the mutant allele?
- Inbreeding in a population is most likely to increase the frequency of which of the following?
- A population experiences a sudden reduction in size due to natural disaster. Which population genetics concept best describes the resulting…
- A small group leaves a large population and establishes a new isolated community. After generations, a previously rare allele becomes more…
- If p = 0.7 in a Hardy-Weinberg population, what is the expected heterozygote frequency?