In Mendel's dihybrid cross (RrYy x RrYy), what is the probability of obtaining an offspring that is homozygous recessive for both traits (rryy)?
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Correct answer: 1/16
In a 16-square Punnett square for a dihybrid cross, only one combination (the bottom right) results in the double recessive genotype. This results in the characteristic 9:3:3:1 phenotypic ratio where '1' represents the double recessive.
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