A dihybrid plant (AaBb) is self-pollinated. What proportion of the offspring will be dihybrid (AaBb) like the parent?
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Correct answer: 4/16
In a dihybrid Punnett square, the genotype AaBb appears in 4 out of the 16 squares (along the diagonal). Thus, 4/16 or 25% of the F2 generation will have the same heterozygous genotype as the F1 parent.
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