A plant of genotype AB/ab is test-crossed. The progeny consist of 40% AB/ab, 40% ab/ab, 10% Ab/ab, and 10% aB/ab. What is the map distance between A and B?
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Correct answer: 20 cM
Map distance equals the total percentage of recombinant progeny. Here, the recombinants are Ab/ab (10%) and aB/ab (10%), totaling 20%. Therefore, the map distance is 20 cM.
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